0=8x^2+2x-5

Solution for 0=8x^2+2x-5 equation:

0=8x^2+2x-5

We move all terms to the left:

0-(8x^2+2x-5)=0

We add all the numbers together, and all the variables

-(8x^2+2x-5)=0

We get rid of parentheses

-8x^2-2x+5=0

a = -8; b = -2; c = +5;
Δ = b2-4ac
Δ = -22-4·(-8)·5
Δ = 164
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{164}=\sqrt{4*41}=\sqrt{4}*\sqrt{41}=2\sqrt{41}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{41}}{2*-8}=\frac{2-2\sqrt{41}}{-16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{41}}{2*-8}=\frac{2+2\sqrt{41}}{-16}
$